Respuesta :
For this case, we have:
[tex]y-yo = m (x-xo) [/tex]
Where,
m: slope of the linear function
(xo, yo): ordered pair that belongs to the linear function.
Since the lines are perpendicular, then the slope is given by:
[tex]m = - \frac{1}{\frac{1}{4}} [/tex]
Rewriting we have:
[tex]m = -4 [/tex]
The line passes through the point (-2, -6), therefore we have:
[tex](xo, yo) = (-2, -6) [/tex]
Substituting values we have:
[tex]y - (- 6) = - 4 (x - (- 2)) [/tex]
Rewriting we have:
[tex]y + 6 = -4 (x + 2) [/tex]
Answer:
An equation of the line that passes through the point (-2, -6) with slope -4 is:
[tex]y + 6 = -4 (x + 2) [/tex]
option B
[tex]y-yo = m (x-xo) [/tex]
Where,
m: slope of the linear function
(xo, yo): ordered pair that belongs to the linear function.
Since the lines are perpendicular, then the slope is given by:
[tex]m = - \frac{1}{\frac{1}{4}} [/tex]
Rewriting we have:
[tex]m = -4 [/tex]
The line passes through the point (-2, -6), therefore we have:
[tex](xo, yo) = (-2, -6) [/tex]
Substituting values we have:
[tex]y - (- 6) = - 4 (x - (- 2)) [/tex]
Rewriting we have:
[tex]y + 6 = -4 (x + 2) [/tex]
Answer:
An equation of the line that passes through the point (-2, -6) with slope -4 is:
[tex]y + 6 = -4 (x + 2) [/tex]
option B