Answer:
[tex]y=-\frac{1}{4}[/tex]
Step-by-step explanation:
We have been given an equation [tex]8y=16y+2[/tex]. We are asked to find the value of y.
First of all, we will subtract 16y from both sides of our equation.
[tex]8y-16y=16y-16y+2[/tex]
[tex]8y-16y=2[/tex]
[tex]-8y=2[/tex]
Now we will divide both sides of our equation by -8.
[tex]\frac{-8y}{-8}=\frac{2}{-8}[/tex]
[tex]y=-\frac{2}{8}[/tex]
[tex]y=-\frac{1}{4}[/tex]
[tex]y=-\frac{1}{4}[/tex]
Therefore, the value of y is [tex]-\frac{1}{4}[/tex].
