The decrease in gravitational potential energy of the system is given by
[tex] \Delta U = (mg) \Delta h [/tex]
where
m is the mass, g is the gravitational acceleration, and [tex] \Delta h [/tex] is the variation of height of the system.
[tex] (mg) [/tex] also corresponds to the weight of the diver, therefore if we rearrange the equation and we use [tex] \Delta U=28000 J [/tex] and [tex] \Delta h=32.0 m [/tex], we can find her weight:
[tex] mg=\frac{\Delta U}{\Delta h}=\frac{28000 J}{32 m}=875 N [/tex]
