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solve and graph the inequality x^2<64

Part 1: take the square root of both sides of inequality

Part 2: recall that √x² < √b is equal to lxl< √b using the inequality from part 1 solve for x 

Part 3: graph your solution from part 2 on the number line provided

Respuesta :

gmany
[tex]x^2 < 64\to\sqrt{x^2} < \sqrt{64}\to|x| < 8\to x < 8\ \wedge\ x > -8\\\\x\in(-8;\ 8)[/tex]
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