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Anna plans a business model to compete with two video stores, where she hopes to draw in customers from one store but not lose money on the deal.

Movie Mania charges a subscription fee of $30 and an additional $5 per movie, x. Movie Time charges a subscription fee of $25 and an additional $6 per movie, x.

Based on this information, which system of inequalities could be used to determine how many movies need to be rented for a customer on Anna’s plan, y, to pay her more than they would at Movie Time, but less than they would at Movie Mania?

Respuesta :

DeanR
Let [tex]x[/tex] be the number of movies, [tex]m(x)[/tex] be how much Movie Mania charges and [tex]t(x)[/tex] be how much Movie Time charges and [tex]a(x)[/tex] be Anna's plan.

Movie Mania charges a subscription fee of $30 and an additional $5 per movie

[tex]m(x)=30+5x[/tex] 

Movie Time charges a subscription fee of $25 and an additional $6 per movie

[tex]t(x)=25+6x[/tex] 

How many movies need to be rented for a customer on Anna’s plan, y, to pay her more than they would at Movie Time, but less than they would at Movie Mania?

That's 

[tex]t(y) < a(y) < m(y)[/tex] 

Expanding it out,

[tex]25+6y< a(y) < 30+5y[/tex] 
  
Is there any room there?

[tex]25+6y < 30+5y[/tex]

[tex]y < 5[/tex]

There's no possible plan that will do what Anna wants for 5 or more movies, because in that domain Movie Time costs more than Movie Mania.  She can squeeze in there between 1 and 4 movies.

I write the answer as:

[tex]25+6y< a(y) < 30+5y[/tex] 

nadiazindani01

Answer:

The person below is right but they just explained it alittle oddly so I'll clarify for them because it is correct :)

y<5x+30/x

y>6x+25/x

Step-by-step explanation:


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