For this case we have the following equation:
Δx = ½ a (Δt) ² + vΔt
Where,
Δx: displacement
a: acceleration
Δt: total time
v: initial speed
Clearing the acceleration we know:
a = 2 (Δx - vΔt) / (Δt) ²
We now perform the calculations.
The total time is:
Δt = 2.85 - 0 = 2.85
Δx = - 5 - 3.18 = - 8.18
v = 10
Substituting values we have:
a = 2 (-8.18 - (10) (2.85)) / (2.85) ²
a = -9.03 cm / s ^ 2
Answer:
The acceleration of the object is:
a = -9.03 cm / s ^ 2:
