Respuesta :
The answer is: " 5 boxes " .
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Explanation:
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Given the formula:
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→ " [tex]Z = \frac{FC}{N} [/tex] " ;
in which:
Z = number of boxes ; ← for which we shall solve ;
F = number of favors each child will get = " 3 " {given} ;
C = number of children at the party = " 25 " {given} ;
N = number of party favors per box = " 15 " {given} ;
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→ Plug these given values into the formula/equation ;
to solve for: " Z " ; the number of boxes .
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→ [tex]Z = \frac{FC}{N} [/tex] ;
→ [tex]Z = \frac{3*25}{15} [/tex] ;
The "3" cancels to a "1" ; and the "15" cancels to "5" ;
→ { since: " 3 ÷ 3 = 1 " ; and since: "15 ÷ 3 = 5 " } ;
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→ And we can rewrite as:
[tex]Z = \frac{1*25}{5} [/tex] ;
→ Note: We change the: "(1 * 25) " (in the "numerator") ; to: " 25 " ;
to simplify; since: "any value", multiplied by "1", results in that same value.
→ As such: "(1 * 25 = 25)" .
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And we can rewrite our equation as:
→ [tex]Z = \frac{25}{5} [/tex] ;
And can further reduce;
→ to solve for our answer, "Z", the "number of boxes"; as follows:
→ [tex]Z = 25 ÷ 5[/tex] ;
→ [tex]Z = " 5 " .
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→ The answer is: " 5 boxes " .
__________________________________________________________
Hope this explanation is helpful!
Please comment if you need further clarification or have any questions.
Best wishes in your academic endeavors!
___________________________________________________________
Explanation:
___________________________________________________________
Given the formula:
___________________________________________________________
→ " [tex]Z = \frac{FC}{N} [/tex] " ;
in which:
Z = number of boxes ; ← for which we shall solve ;
F = number of favors each child will get = " 3 " {given} ;
C = number of children at the party = " 25 " {given} ;
N = number of party favors per box = " 15 " {given} ;
___________________________________________________________
→ Plug these given values into the formula/equation ;
to solve for: " Z " ; the number of boxes .
___________________________________________________________
→ [tex]Z = \frac{FC}{N} [/tex] ;
→ [tex]Z = \frac{3*25}{15} [/tex] ;
The "3" cancels to a "1" ; and the "15" cancels to "5" ;
→ { since: " 3 ÷ 3 = 1 " ; and since: "15 ÷ 3 = 5 " } ;
____________________________________________________________
→ And we can rewrite as:
[tex]Z = \frac{1*25}{5} [/tex] ;
→ Note: We change the: "(1 * 25) " (in the "numerator") ; to: " 25 " ;
to simplify; since: "any value", multiplied by "1", results in that same value.
→ As such: "(1 * 25 = 25)" .
___________________________________________________________
And we can rewrite our equation as:
→ [tex]Z = \frac{25}{5} [/tex] ;
And can further reduce;
→ to solve for our answer, "Z", the "number of boxes"; as follows:
→ [tex]Z = 25 ÷ 5[/tex] ;
→ [tex]Z = " 5 " .
__________________________________________________________
→ The answer is: " 5 boxes " .
__________________________________________________________
Hope this explanation is helpful!
Please comment if you need further clarification or have any questions.
Best wishes in your academic endeavors!