The triangle formed by the building, its shadow and the line between the end of shadow to top of the building has the following values:-
adjacent side = 88 m, angle of elevation = 32 degrees and we need to find the length of the opposite side ( that is height of the building).
A = 88 , m < elevation = 32 and O = ?
SOH-CAH-TOA - so we need the tan of 32:-
tan 32 = O / 88
O = 88 * tan 32 = 55m to nearest meter ( answer)