Answer : 9.293 g
Explanation : The reaction is
[tex] C_{4}H_{8}O_{2} + C_{2}H_{5}OH ----\ \textgreater \ C_{6}H_{12}O_{2} + H_{2}O[/tex]
Here, if we assume the stoichiometric esterification ratio as 1:1 then,
no. of moles of [tex]C_{4}H_{8}O_{2}[/tex] = 7.05 g/ 88 = 8.011 [tex]X 10^{-2} [/tex] moles
so here, no. of moles of ethyl butyl rate = no. of moles of butyric acid ;
[tex] \frac{m (C_{4}H_{8}O_{2})}{M (C_{4}H_{8}O_{2})} = \frac{m (C_{6}H_{12}O_{8})}{M (C_{6}H_{12}O_{8})} [/tex]
[tex]m(C_{6}H_{12}O_{8}))[/tex] = (7.05 /88.11) X 116.16 = 9.29 g
