Respuesta :
[tex]\bf \stackrel{\textit{slope or derivative}}{-\cfrac{x}{y}}\qquad (\stackrel{x}{3},\stackrel{y}{-4})\qquad \left. -\cfrac{x}{y} \right|_{3,-4}\implies -\cfrac{3}{-4}\implies \stackrel{\stackrel{slope}{m}}{\cfrac{3}{4}}\\\\
-------------------------------\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-4)=\cfrac{3}{4}(x-3)
\implies
y+4=\cfrac{3}{4}x-\cfrac{9}{4}
\\\\\\
y=\cfrac{3}{4}x-\cfrac{9}{4}-4\implies y=\cfrac{3}{4}x-\cfrac{25}{4}[/tex]
The differential equation
dy/dx = -x/y
is a separable differential equation that has the solution
x^2 + y^2 = c
Substituting the given values for x and y, we find c=25.
The desired equation is
x^2 + y^2 = 25
dy/dx = -x/y
is a separable differential equation that has the solution
x^2 + y^2 = c
Substituting the given values for x and y, we find c=25.
The desired equation is
x^2 + y^2 = 25