Respuesta :

T₁ = 27°C = 27 + 273 = 300K,  V₁ = 6 L,

T₂ = 150°C = 150 + 273 = 423K,  V₂ = ?,

By Charles' Law:      V₁/T₁= V₂/T₂

                                 6/300 = V₂/423

                                  423*(6/300) = V₂

                                  8.46 = V₂

           Volume at 150°C =8.46 L.

To calculate the volume of gas at 150°C, we use Charles's law

Charles's law

It states that the volume of a fixed mass of gas is directly proportional to its temperature, provided the pressure remains constant.

From Charles law,

  • V₁/T₁ = V₂/T₂........... Equation 1

Where:

  • V₁ = Initial volume of gas
  • T₁ = Initial temperature of gas
  • V₂ = Final volume of gas
  • T₂ = Final temperature of gas

Make V₂ the subject of the equation

  • V₂ = (V₁×T₂)/T₁................ Equation 2

From the question,

Given:

  • V₁ = 6 L
  • T₁ = 27 °C = (27+273) = 300 K
  • T₂ = 150 °C = (150+273) = 423 K

Substitute these values into equation 2

  • V₂ = (6×423)/300
  • V₂ = 8.46 L

Hence, the volume of the gas at 150 °C is 8.64 L

Learn more about Charles law here: https://brainly.com/question/888898