Respuesta :
T₁ = 27°C = 27 + 273 = 300K, V₁ = 6 L,
T₂ = 150°C = 150 + 273 = 423K, V₂ = ?,
By Charles' Law: V₁/T₁= V₂/T₂
6/300 = V₂/423
423*(6/300) = V₂
8.46 = V₂
Volume at 150°C =8.46 L.
T₂ = 150°C = 150 + 273 = 423K, V₂ = ?,
By Charles' Law: V₁/T₁= V₂/T₂
6/300 = V₂/423
423*(6/300) = V₂
8.46 = V₂
Volume at 150°C =8.46 L.
To calculate the volume of gas at 150°C, we use Charles's law
Charles's law
It states that the volume of a fixed mass of gas is directly proportional to its temperature, provided the pressure remains constant.
From Charles law,
- V₁/T₁ = V₂/T₂........... Equation 1
Where:
- V₁ = Initial volume of gas
- T₁ = Initial temperature of gas
- V₂ = Final volume of gas
- T₂ = Final temperature of gas
Make V₂ the subject of the equation
- V₂ = (V₁×T₂)/T₁................ Equation 2
From the question,
Given:
- V₁ = 6 L
- T₁ = 27 °C = (27+273) = 300 K
- T₂ = 150 °C = (150+273) = 423 K
Substitute these values into equation 2
- V₂ = (6×423)/300
- V₂ = 8.46 L
Hence, the volume of the gas at 150 °C is 8.64 L
Learn more about Charles law here: https://brainly.com/question/888898