Easy, there are two methods,
Method One, combine the two common factors of 13-2x by adding the exponents. Making the answer,
(13-2[tex] x)^{2} [/tex]
The other method is by multiplying it out, using FOIL (First, Outer, Inner, Last)
switch
(13-2x)(13-2x)
to
(-2x+13)(-2x+13) now you can multiply,
take, FIRST, -2x*-2x
=[tex] 4x^{2} [/tex]
then, OUTER, -2x*13
=-26x
then, INNER, 13*-2x
=-26x
finally, LAST, 13*13
=169
Finally, add, the sum together.
4[tex] x^{2} [/tex]-26x-26x+169
4[tex] x^{2} [/tex]-52x+169.
This, is your answer.
