check the picture below.
[tex]\bf \textit{area of a circle}\\\\
A=\pi r^2~~
\begin{cases}
r=radius\\
-----\\
A=144\pi
\end{cases}\implies 144\pi =\pi r^2
\\\\\\
\cfrac{144\pi }{\pi }=r^2\implies 144=r^2\implies \sqrt{144}=r\implies \boxed{12=r}\\\\
-------------------------------[/tex]
[tex]\bf \textit{since the sphere then, has a \underline{radius of 12}}
\\\\\\
\textit{volume of a sphere}\\\\
V=\cfrac{4\pi r^3}{3}\qquad \implies V=\cfrac{4\pi (12)^3}{3}\implies V=2304\pi
\\\\\\
\textit{surface area of a sphere}\\\\
SA=4\pi r^2\qquad \implies SA=4\pi (12)^2\implies SA=576\pi [/tex]
