[tex]\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 6.25\%\to \frac{6.25}{100}\to &0.0625\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &10
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.0625}{4}\right)^{4\cdot 10}
\\\\\\
A=10000(1.015625)^{40}\implies A\approx 18592.39366677226890[/tex]
