Answer:
The value of the given operation is 25.
Step-by-step explanation:
We where given a rule of operation called [tex]\otimes[/tex] with the form
[tex]a\otimes b=(2a-1)^{b-1}[/tex]
where a and b are positive integers. Then we where asked to calculate
[tex](2\otimes 2)\otimes 3[/tex]
In order to do it, we have to make two calculations, evaluating this operation properly each time... First we calculate the parentesis as it is the operation of higher hierarchy:
[tex](2\otimes 2)=(2*2-1)^{2-1}=(4-1)^1=3[/tex]
then, we replace that outcome in the second calculation
[tex](2\otimes 2)\otimes 3=3\otimes 3=(2*3-1)^{3-1}=(6-1)^2=5^2=25[/tex]
which is the value asked in the problem.
