The given ratio of powder to water is 3:2 based on weight for Kool-aide. It is also given that 120g of flavored powder is needed for a certain amount of Kool-aide.
Let us assume that the amount of water (by weight) required to maintain the given ratio of 3:2 be represented by the letter [tex] x [/tex]. Thus, from the given information we can conclude that:
[tex] \frac{Powder Weight}{Water Weight}=\frac{3}{2}=\frac{120}{x} [/tex]
[tex] \therefore \frac{3}{2}=\frac{120}{x} [/tex]
Cross-multiplying we get:
[tex] 3x=240 [/tex]
[tex] \therefore x=\frac{240}{3}=80 [/tex] grams.
Thus, the amount of water in grams in that Kool-aide is 80 grams.
