Respuesta :

claudettoterohil
your answer would be (D), 5.02 x 10^24 atoms
Mass of H2O is 18.01
75.0 grams = 75.0/18.01 = 4.16 moles
hydrogen atoms = 2(4.16)(6.022 * 1023)

Answer = 5.02 x 1024 atoms




Second solution:
molar mass H2O = 18g/mole
75g H2O = 75/18 = 4.167mole
Molecules in 1 mole = 6.022 x 10^23
Molecules in 4.167 
mole = 4.167(6.022)(10^23) = 2.51(10^24moles)
each H2O molecules contains 2 H Atoms
So, Number of H Atoms = 2.51(10^24)2 
Answer = 5.02 x 10^24




Hope that answers your question!!!! have a great day!!!
onyebuchinnaji

The number of hydrogen atoms present in 75 grams of water is 5.02 x 10²⁴ atoms.

The given parameters;

  • mass of the water given = 75 g

The molecular mass of water is calculated as follows;

H₂O = (2x 1) + (16) = 18 g/mol

The number of moles of 75 g of water is calculated as follows;

[tex]n = \frac{m}{Mw} = \frac{75}{18} = 4.167 \ moles[/tex]

The number of atoms present in 4.167 moles of water is calculated as follows;

[tex]no \ atoms = 4.167(6.02 \times 10^{23} \ atoms)\\\\no \ atoms = 2.51 \times 10^{24} \ atoms[/tex]

The hydrogen atoms present is calculated as;

[tex]no \ of \ hydrogen \ atoms , \ H_2O , \ = 2(2.51 \times 10^{24} \ atoms) = 5.02 \times 10^{24} \ atoms \\\\[/tex]

Thus, the number of hydrogen atoms present in 75 grams of water is 5.02 x 10²⁴ atoms.

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