Respuesta :
[tex]\bf A(t)=942e^{-0.012t}\qquad \boxed{\stackrel{\textit{after 71 years}}{t=71}}\qquad \qquad A(t)=942e^{-0.012(71)}
\\\\\\
A(t)\approx 401.82042087707606813879[/tex]
Applying the exponential function, it is found that the amount after 71 years is of 402 mg.
The exponential equation for the amount after t years is given by:
[tex]A(t) = 942e^{-0.012t}[/tex]
For the amount after 71 years, we find A(71), thus:
[tex]A(71) = 942e^{-0.012(71)} = 402[/tex]
The amount after 71 years is of 402 mg.
A similar problem is given at https://brainly.com/question/16959384
