Part A is accomplished by first factoring out the b^2 to get[tex] b^{2} (5 x^{2} +14x-3)[/tex]. Factor that completely using the quadratic formula to get [tex] b^{2} (x+3)(5x-1)[/tex]. Part B is done entirely with the quadratic formula (only cuz that's the easiest way to factor a second degree polynomial!) to get (x-9)(x-9) or (x-9) multiplicity 2. Part C is done by taking roots. Keep in mind that since this is a second degree polynomial you will have 2 solutions. [tex] x^{2} -121=0[/tex], therefore, [tex] x^{2} =121[/tex] and [tex]x=+/- \sqrt{121} [/tex] which is +11 and -11. And you're done! Factoring is very important...make sure you learn it and learn it well!!!
